Aktosun, Spring 2023,
Math 5322, Supplementary Problems 1
- Simplify the following:
- (3i34-i23)/(2i-1).
solution:
1+i.
- (-11-2i)1/3.
solution:
1251/6exp(πi/3+ia/3),
1251/6exp(-πi/3+ia/3),
and -1251/6exp(ia/3),
where a=tan-1(2/11).
- Solve the following equations:
- z2-(2i+3)z+5+i=0.
solution:
1-i and 2+3i.
- 6z4-25z3+32z2+3z=10.
solution:
-1/2, 2/3, 2±i.
- z2(1-z2)=16.
solution:
(3±71/2i)/2 and
(-3±71/2i)/2.
- (1+z)5=(1-z)5.
solution:
0, ±i[5-201/2]1/2,
±i[5+201/2]1/2.
- Explain how the following basic functions are defined and state whether
each function is single valued, double valued, etc.
- zn, n=0,1,2,....
- 1/zn, n=0,1,2,....
- ez.
- trigonometric functions.
- hyperbolic functions.
- log(z).
- inverse trigonometric functions.
- inverse hyperbolic functions.
- zw.
- Prove the following or disprove with a counterexample:
- |sin(z)|≤1.
- |cos(z)|≤1.
- |sin(z)|≤|z|.
- sin2z+cos2z=1.
- sec2z-tan2z=1.
- sin(z1+z2)=(sinz1)(cosz2)+(cosz1)(sinz2)
- cos(z1+z2)=(cosz1)(cosz2)+(sinz1)(sinz2)
- ||z1|-|z2||≤|z1+z2|≤|z1|+|z2|.
- ||z1|-|z2||≤|z1-z2|≤|z1|+|z2|.
- |Re(z)|≤|z|.
- |Im(z)|≤|z|.
- |zn|=|z|n, n=0,1,2,....
- |1/zn|=1/|z|n, n=1,2,....
- |ez|=eRe(z).
- Prove the following:
- |z1+z2|2+|z1-z2|2=2(|z1|2+|z2|2).
hint:
use |z|2=zz*
for each of the complex numbers z1+z2,
z1-z2, z1, and z2.
- cos(2π/n)+cos(4π/n)+cos(6π/n)+...+cos(2(n-1)π/n)=-1.
hint:
let w=exp(i2π/n),
use 1+w+w2+...+wn-1=(1-wn)/(1-w) with wn=1 and take the real parts.
- sin(2π/n)+sin(4π/n)+sin(6π/n)+...+sin(2(n-1)π/n)=0.
hint:
let w=exp(i2π/n),
use 1+w+w2+...+wn-1=(1-wn)/(1-w) with wn=1 and take the imaginary parts.
- sin(3x)=3sinx-4sin3x.
hint:
use De Moivre's theorem with n=3 and use
the imaginary parts in the resulting equation.
- cos(4x)=8sin4x-8sin2x+1.
hint:
use De Moivre's theorem with n=4 and use
the real parts in the resulting equation.
- Describe the following families of curves in the complex plane:
- Re(1/z)=C.
solution:
family of circles centered at 1/(2C)+0i of
radius 1/|2C| but with the origin excluded.
- Im(1/z)=C.
solution:
family of circles centered at 0-i/(2C) of
radius 1/|2C| but with the origin excluded.
- Re(z2)=C.
solution:
family of hyperbolas x2-y2=C
on the xy plane
centered at the origin; when C=0 we have the lines
y=±x.
- Im(z2)=C.
solution:
family of hyperbolas xy=C/2
on the xy plane
centered at the origin; when C=0 we have the
x and y axes.
- Evaluate the following:
- 1+2w+3w2+...+nwn-1,
where w is an nth root of unity.
solution:
n(n+1)/2 if w=1, n/(w-1) if w≠1.
- 1+4w+9w2+...+n2wn-1
,
where w is an nth root of unity.
solution:
n(2n+1)(n+1)/6 if w=1, [n2w2-2n(n+1)w+n(n+2)]/(w-1)3 if
w≠1.
- For a function f(z), relate the following to each other:
- existence of the derivative of f at z0
- differentiability of f at z0
- differentiability of Re(f) and Im(f)
and the validity of the Cauchy-Riemann equations at z0
- differentiability of f in z, z* at z0 and ∂f/∂z* being zero at z0
- analyticity of f at z0
solution:
1, 2, 3, and 4 are equivalent; 5 holds if and only if the conditions
in any one of 1, 2, 3, and 4 hold also in a neighborhood of z0;
for example f(z)=|z|2 is not analytic
at z=0 but it is differentiable at z=0.
- For a function f(z) defined on a domain
W, relate the following to each other:
- existence of the derivative of f on W
- differentiability of f on W
- differentiability of f in z, z* on W and ∂f/∂z* being zero on W
- differentiability of Re(f) and Im(f)
and the validity of the Cauchy-Riemann equations on W
- analyticity of f on W
solution:
1, 2, 3, 4, and 5 are equivalent.
- For a function f(z) differentiable in z, z* on a domain
W, express ∂f/∂z
and ∂f/∂z* in terms of
the x and y derivatives of Re(f) and Im(f).
solution:
∂f/∂z=(ux+vy)/2+i(vx-uy)/2 and ∂f/∂z*=(ux-vy)/2+i(vx+uy)/2, where u:=Re(f) and v:=Im(f).
- For a function f(z) differentiable on a domain
W, express ∂f/∂z and
∂f/∂z* in terms of
the x and y derivatives of Re(f) and Im(f).
solution:
∂f/∂z=ux+ivx=ux-iuy=vy-iuy=vy+ivx and ∂f/∂z*=0, where u:=Re(f) and v:=Im(f).
- For a function f(z) differentiable on a domain
W, express df/dz in terms of
the x and y derivatives of Re(f) and Im(f).
solution:
df/dz=ux+ivx=ux-iuy=vy-iuy=vy+ivx, where u:=Re(f) and v:=Im(f).
- For the following function, study the existence of the derivative
at z=0,
differentiability at z=0, analyticity at z=0,
and validity of the Cauchy-Riemann equations at z=0:
- f(z)=Re(z).
solution:
f′(0) does not exists;
f is not differentiable at z=0;
f is not analytic at z=0;
ux(0,0)≠vy(0,0) but
uy(0,0)=-vx(0,0)
because we have ux(0,0)=1, uy(0,0)=0,
vx(0,0)=0,
and vy(0,0)=0.
- f(z)=Im(z).
solution:
f′(0) does not exists;
f is not differentiable at z=0;
f is not analytic at z=0;
ux(0,0)=vy(0,0) but
uy(0,0)≠-vx(0,0)
because we have ux(0,0)=0, uy(0,0)=1,
vx(0,0)=0,
and vy(0,0)=0.
- f(z)=|z|.
solution:
f′(0) does not exists;
f is not differentiable at z=0;
f is not analytic at z=0;
ux(0,0)≠vy(0,0) and
uy(0,0)≠-vx(0,0)
because ux(0,0) does not exist,
uy(0,0) does not exist,
vx(0,0)=0,
and vy(0,0)=0.
- f(z)=z·Re(z).
solution:
f′(0)=0;
f is differentiable at z=0;
f is not analytic at z=0;
ux(0,0)=vy(0,0) and
uy(0,0)=-vx(0,0)
because ux(0,0)=0,
uy(0,0)=0,
vx(0,0)=0,
and vy(0,0)=0.
- f(z)=|Re(z)·Im(z)|.
solution:
f′(0)=0;
f is differentiable at z=0;
f is not analytic at z=0;
ux(0,0)=vy(0,0) and
uy(0,0)=-vx(0,0)
because ux(0,0)=0,
uy(0,0)=0,
vx(0,0)=0,
and vy(0,0)=0.
- f(z)=|z|2.
solution:
f′(0)=0;
f is differentiable at z=0;
f is not analytic at z=0;
ux(0,0)=vy(0,0) and
uy(0,0)=-vx(0,0)
because ux(0,0)=0,
uy(0,0)=0,
vx(0,0)=0,
and vy(0,0)=0.
- f(z)=|z|4.
solution:
f′(0)=0;
f is differentiable at z=0;
f is not analytic at z=0;
ux(0,0)=vy(0,0) and
uy(0,0)=-vx(0,0)
because ux(0,0)=0,
uy(0,0)=0,
vx(0,0)=0,
and vy(0,0)=0.
- f(z)=z2z*.
solution:
f′(0)=0;
f is differentiable at z=0;
f is not analytic at z=0;
ux(0,0)=vy(0,0) and
uy(0,0)=-vx(0,0)
because ux(0,0)=0,
uy(0,0)=0,
vx(0,0)=0,
and vy(0,0)=0.
- any polynomial in z.
solution:
the derivative exists everywhere and in particular at
z=0;
differentiable everywhere and in particular at
z=0;
analytic everywhere and in particular at
z=0;
ux=vy
and uy=-vx everywhere
and in particular at
z=0.
- sin(z).
solution:
the derivative exists everywhere and in particular at
z=0;
differentiable everywhere and in particular at
z=0;
analytic everywhere and in particular at
z=0;
ux=vy
and uy=-vx everywhere
and in particular at
z=0.
- ez.
solution:
the derivative exists everywhere and in particular at
z=0;
differentiable everywhere and in particular at
z=0;
analytic everywhere and in particular at
z=0;
ux=vy
and uy=-vx everywhere
and in particular at
z=0.
- 1/(z+7+i).
solution:
the derivative exists everywhere except at z=-7-i,
and in particular it exists at
z=0;
differentiable everywhere except at z=-7-i,
and in particular differentiable at
z=0;
analytic everywhere except at z=-7-i,
and in particular analytic at
z=0;
ux=vy
and uy=-vx everywhere
except at z=-7-i,
and in particular these equations hold at z=0.
- For the following function, find the partial derivative with respect to
z, the partial derivative with respect to z*, and the derivative at z=0:
- f(z)=Re(z).
solution:
1/2, 1/2, does not exist.
- f(z)=Im(z).
solution:
-i/2, i/2, does not exist.
- f(z)=|z|.
solution:
does not exist, does not exist, does not exist.
- f(z)=z·Re(z).
solution:
0, 0, 0.
- f(z)=|Re(z)·Im(z)|.
solution:
0, 0, 0.
- f(z)=|z|2.
solution:
0, 0, 0.
- f(z)=|z|4.
solution:
0, 0, 0.
- f(z)=z2z*.
solution:
0, 0, 0.
- any polynomial in z.
solution:
the coefficient of z in the polynomial, 0,
the coefficient of z in the polynomial.
- sin(z).
solution:
1, 0, 1.
- ez.
solution:
1, 0, 1.
- 1/(z+7+i).
solution:
-1/(7+i)2, 0, -1/(7+i)2.
- If z=-1-i, evaluate the following:
- Arg(z).
solution:
-3π/4.
- Arg(z2).
solution:
π/2.
- Arg(1/z).
solution:
3π/4.
- Arg(z*).
solution:
3π/4.
- Arg(1/z*).
solution:
-3π/4.
- Arg(1/z5).
solution:
-π/4.
- If z=-1+i, evaluate the following:
- arg(z).
solution:
3π/4+2πn, where
n is any integer.
- arg(z2).
solution:
-π/2+2πn.
- arg(1/z).
solution:
-3π/4+2πn.
- arg(z*).
solution:
-3π/4+2πn.
- arg(1/z*).
solution:
3π/4+2πn.
- arg(1/z5).
solution:
π/4+2πn.
- If f(z)=x2-y2-2y+2ix-2ixy, find the following:
- ∂f/∂z.
solution:
2i.
- ∂f/∂z*.
solution:
2z*.
- df/dz.
solution:
2i at z=0, does not exist elsewhere.
- all the points at which f is analytic.
solution:
nowhere analytic.
- all the points at which f is differentiable.
solution:
only at z=0.
- all the points at which f is continuous.
solution:
everywhere continuous.
- If g(z)=x3-3xy2+x+1+3ix2y+iy-iy3, find the following:
- ∂g/∂z.
solution:
3z2+1.
- ∂g/∂z*.
solution:
0.
- dg/dz.
solution:
3z2+1.
- all the points at which g is analytic.
solution:
everywhere analytic.
- all the points at which g is differentiable.
solution:
everywhere differentiable.
- all the points at which g is continuous.
solution:
everywhere continuous.
- If f(z)=(x2y+xy2)/(x3+y3) for z≠0 and
f(z)=0 for z=0, find the following:
- ux(0,0), where
u(x,y)=Re[f(z)].
solution:
ux(0,0)=0.
- vx(0,0),
where v(x,y)=Im[f(z)].
solution:
vx(0,0)=0.
-
is u(x,y) continuous at (0,0)?
solution:
not continuous.
-
is u(x,y) differentiable at (0,0)?
solution:
not differentiable.
-
is v(x,y) continuous at (0,0)?
solution:
continuous.
-
is v(x,y) differentiable at (0,0)?
solution:
differentiable.
- is f continuous at z=0?
solution:
not continuous.
- is f differentiable at z=0?
solution:
not differentiable.
- do the Cauchy-Riemann equations hold at (0,0)?
solution:
the Cauchy-Riemann equations hold at (0,0).
- is f analytic at z=0?
solution:
not analytic.
- If f(z)=(x2y-xy2)/(x2+y2) for z≠0 and
f(z)=0 for z=0, find the following:
- ux(0,0), where
u(x,y)=Re[f(z)].
solution:
ux(0,0)=0.
- vx(0,0),
where v(x,y)=Im[f(z)].
solution:
ux(0,0)=0.
-
is u(x,y) continuous at (0,0)?
solution:
continuous.
-
is u(x,y) differentiable at (0,0)?
solution:
not differentiable.
-
is v(x,y) continuous at (0,0)?
solution:
continuous.
-
is v(x,y) differentiable at (0,0)?
solution:
differentiable.
- is f continuous at z=0?
solution:
continuous.
- is f differentiable at z=0?
solution:
not differentiable.
- do the Cauchy-Riemann equations hold at (0,0)?
solution:
the Cauchy-Riemann equations hold at (0,0).
- is f analytic at z=0?
solution:
not analytic.
- Prove the following:
- |z1+z2|≤|z1|+|z2|
with the equality holding if and only of the real part of z1z2*
is nonnegative.
- the Cauchy-Riemann equations ux=vy and
uy=-vx in the rectangular form can be written as
ur=(1/r)vθ and
vr=-(1/r)uθ in the polar form.
Tuncay Aktosun
aktosun@uta.edu
Last modified: February 16, 2022